Let \(D_{4} = x\) and \(D_{1} = y\). If two sides of a triangle are equal, the angles opposite to these sides are equal. (C) b) Name three sets of angles that are equal. Earn a badge for having successfully completed the tutorial and assignment. NX^{2} &= VX.TX & \\ \therefore \dfrac{h}{c}&= \dfrac{a}{d} & \\ })\\ Provide learner with additional knowledge and understanding of the topic; \end{array}\], \[\begin{array}{rll} Chord \(ST\) is produced to \(W\). \therefore TU & = VU = 35 & \quad \text{(isosceles } \triangle \text{)} \\ & & \\ Euclidean Geometry (T2) Term 2 Revision; Analytical Geometry; Finance and Growth; Statistics; Trigonometry; Euclidean Geometry (T3) Measurement; Term 3 Revision; Probability; Exam Revision; Grade 11. Use the theorem of Pythagoras to determine \(YT\): Use proportionality to determine \(XZ\) and \(YZ\): Given the following figure with the following lengths, find \(AE\), \(EC\) and \(BE\). In \(\triangle RSN\) and \(\triangle RMS\): \(AC\) is a diameter of circle \(ADC\). Determine \(\frac{HJ}{KI}\). })\\ &= 25 - \text{8,3} & \\ \end{array}\], \[\begin{array}{rll} \[\begin{array}{rll} & = \frac{(10)(35)}{20} & \\ & & \\ \(RS\) is a tangent to the circle and \(ER \perp MR\). \frac{SW}{WT} & = \frac{SV}{VU} & \quad \text{(proportion Theorem)} \\ Support knowledge, grasp and understanding, by completing a digital, interactive assignment. at Everything Maths.Alternatively, access the following online texts specific to geometry: \text{But } RS &= RE & \\ \hat{P}_{1} & = \text{40}° & \qquad(\angle \text{s in same seg.}) & & \\ B\hat{D}C&= \hat{A_{1}} & (\angle \text{s on same chord}) \\ \begin{align*} JI & = JK+KI \\ & = \frac{5}{3}KI+KI \\ & = \frac{8}{3}KI \\ \frac{JI}{KI} & = \frac{8}{3} \\ & \\ \frac{HJ}{KI} & = \frac{HJ}{JI} \times \frac{JI}{KI} \\ & = \frac{5}{3}\times \frac{8}{3} \\ & = \frac{40}{9} \end{align*}, \[\begin{array}{rll} Slope Wikipedia. \therefore F\hat{E}D & = \hat{D} & \\ In this live Grade 11 and 12 Maths show we take a look at Euclidean Geometry. \angle \text{s}, GF \parallel ED) \\ & & \\ Is this correct? \therefore BD & \parallel EF & (\text{alt. } The outer boundaries of the lunes are semicircles of diameters \(AB\) and \(AC\) respectively, and the inner boundaries are formed by the circumcircle of the triangle \(ABC\). 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