A graph of uv against u+v; From the mirror formula, we have; 1/f=1/u + 1/v =(v+u)/uv. An image is only erect when it is a virtual image, therefore virtual images = positive magnification. Here u is the object distance and c is the image distance. Thus A mirror formula can be defined as the formula which gives the relationship between the distance of object ‘u’, the distance of image ‘v’, and the focal length of the mirror ‘f’. If the value of magnification is more than 1, then the image formed is enlarged, and if the value of magnification is less than 1, then the image formed is diminished. Substituting in the mirror formula, we obtain; 1/f=1/u i.e the x-intercept is equal to 1/f. Most noteworthy, in this way the magnification expression will be: m = h’ / h = -v / u. As a demonstration of the effectiveness of the mirror equation and magnification equation, consider the following example problem and its solution. Like the plants, cell, atoms, microorganisms and many more. m = -v / u. Vice versa, magnification is negative when the image is inverted, therefore a real image. Similarly, at the x-intercept 1/v=0. However using the equation m = v/u, m is negative when v is negative. Answer: The magnification is 1 Explanation: Magnification is defined as ratio to a image height to object height, which can be mathematically proven to be same as ratio of image distance to object distance.. Magnification of a mirror is used in many cases. Determine the image distance and the image size. In magnification, I keep on confusing the signs. Generally the convex mirror has magnification greater than 1 and magnification of concave mirror has less than 1. An image is only erect when it is a virtual image, therefore virtual images = positive magnification. Vice versa, magnification is negative when the image is inverted, therefore a real image. And v is only negative when the image is on the same side of the lens as the object. Example of magnification. If v is the distance of image from the mirror or lens and u is the distance of the object from the mirror or lens and f is the focal length of the mirror or lens then Mirror formula: 1/v+1/u=1/f Lens formula: 1/v-1/u… Its example can be any object that we can magnify. Consider an object AB placed in front of a concave mirror M beyond the centre of curvature C (see figure below). The mirror formula is applicable for both, plane mirrors and spherical mirrors (convex and concave mirrors). Example Problem #1 A 4.00-cm tall light bulb is placed a distance of 45.7 cm from a concave mirror having a focal length of 15.2 cm. Solved Question for You. convex mirror formula But DE = AB and when the aperture is very small EF = PF. Let AB be an object placed on the principal axis of a convex mirror of focal length f. u is the distance between the object and the mirror and v is the distance between the image and the mirror. Question. 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